Year 9 Maths Chapter 4 – Linear Relationships
You will want to refer to Year 8 Maths Chapter 3 for basic measurement. This section is more advanced, and omits basic concepts.
Table of Contents
New formulae
- Surface area of a rectangular prism:
A = 2(xy + xz + yz)
wherex
,y
andz
are length, breadth and height. - Volume of a cylinder:
A = 𝜋r²
- Surface area of a cylinder:
A = 2𝜋r² + 2𝜋rh
where2𝜋r²
is the 2 circular ends and2𝜋rh
is the curved area. If you wanted an open cylinder with only one end closed you would remove the 2 in front of the first term. - Volume of a sphere:
(4/3)𝜋r³
- Surface area of a sphere:
4𝜋r²
- Surface area of a square based pyramid:
A = b² + 2bs
whereb
is one base side ands
is the slant height.
Note that for square based pyramids, you might need to use Pythag to find the slant height. This does not equal the height of the pyramid.
In the above image, h
is the height and s
is the slant height. By using Pythag you can solve for s
by using the equation: h² + (b/2)² = s²
.
Formulae to revise
Circles
- Circumference of a circle:
C = 2𝜋r
orC = 𝜋d
- Area of a circle:
A = 𝜋r²
𝜋 = ~22/7
or𝜋 = 3.14 (2dp)
- A sector is a portion of a circle.
- Perimeter of a sector:
P = 2r + θ/360 x 2𝜋r
- Area of a sector:
A = 𝜋r² x θ/360
Rhombus, Kite, Trapezium and Parallelogram
- Rhombus:
pq/2
wherep
andq
are diagonalslb
wherel
is length andb
is height
- Kite:
pq/2
wherep
andq
are diagonalsxy/2
wherex
is width andy
is height
- Trapezium:
a+b/2 x h
wherea
andb
are the parallel sides andh
is the height - Parallelogram:
lb
wherel
is length andb
is height
Please tell me you know what the area of squares, rectangles and triangles are. Marcus probably doesn’t.
Composite shapes
Shapes that are made up of more than one basic shape. To solve for the area or perimeter of composite shapes, you might need to use addition or subtraction. I know how hard that is for you, Marcus.