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Quadratics Cheat Sheet

This document was converted from Google Docs to Microsoft Word Format with XML Format (.docx)(not to be confused with .doc which is Office 97-2003 format) and then to unfiltered HTML (.html). It does look pretty good but there are always things to note when you're working off something like this. Firstly, the source for this is a HTML document instead of GFM so it's not human-readable. Secondly, `jekyll build` seems to not like the Therefore sign and has changed anything in a container with it to Times New Roman. I'm not sure how this actually translates on the remote repo but that's what I'm getting locally. The Google Docs version of this is much better anyway:

© Adrian Widjaja 2019 https://www.youtube.com/watch?v=v9ZlVr38HbE - https://www.youtube.com/watch?v=gIuMU8UBxR4

 

Expand: Binomial Products

FORMULA

RULE

EXAMPLE

   (a+b)(c+d)

= ac+ad+bc+bd

Use FOIL

   (3x + 5)(2x + 3)

= 6x²+ 6x + 10x + 15

= 6x² + 16x + 16

 

Expand: Perfect Squares

FORMULA

RULE

EXAMPLE

   (a+b)2 or (a+b)(a+b)

= a2+2ab+b2

Square the first

2x the product of the middle

Square the last

  (2x - 3)²

= 4x² - 12x + 9

 

Expand: Difference of Two Squares

FORMULA

RULE

EXAMPLE

   (a+b)(a-b)

= a²–b²

Square the first minus square the last

  (3x + 2y)(3x - 2y)

= 9x² - 4y²

 

 

 

Factor: Difference of Two Squares

FORMULA

RULE

EXAMPLE

   a²-b²

= (a+b)(a-b)

Find the root of b term and solve as shown in the formula

   x² - 9

= (x+3)(x-3)

 

Quick Note: Factoring

FORMULA

EXPLANATION

EXAMPLE

   a(b-c)
= -a(c-b)

 

Also consider:

 

    a(b-c)

= -a(c-b) = -a(-b+c)

Essentially is the inverse operation of the brackets, flipping the terms around. Used to help simplify.

   x(x-5) - 2(5-x)

= x(x-5) - 2(-x+5)

= x(x-5) + 2(x-5)

= (x-5)(x+2)

 

 

Quick Note: Difference of Two Squares

FORMULA

RULE

EXAMPLE

   x²–(a+b)²

= (x-(a+b))(x+(a+b))
= (-a)(x+a+b)

NA

   4–(x+2)² 

= (2–(x+2))(2+(x+2))

= (-x)(2+x+2)

= -x(x+4)

 

 

Factor: Monic Trinomials

FORMULA

RULE

EXAMPLE

Where p and q are factors of c that add to make b

 

   x²+bx+c

= (x+p)(x+q)

 

Note:

px + qx = bx

   ∴ p + q = b

pq = c

Find two integers that multiply to c and add to b

 

then write it in the form (x+p)(x+q) where p and q are the two numbers.

x²+9x+20

=(x+4)(x+5)

 

 

Expand into a Monic Trinomial

FORMULA

RULE

EXAMPLE

   (x+a)(x+b)

= x²+ax+bx+ab
= x²+x(a+b)+ab

=  x²+bx+c

Use FOIL

Factorise the middle terms

  (x+5)(x+3)

= x²+3x+5x+15

= x²+x(3+5)+15

= x²+8x+15 

 

 

Grouping in Pairs

FORMULA

RULE

EXAMPLE

Where p and q are integers that add to ab and multiply to c:

 

   x²+ax+bx+c
=  x(x+p)+q(x+p)
=  (x+p)(x+q)

Group the 4 terms into pairs and take out the common binomial factor

 

*Also read Expand into a Monic Trinomial

   x²+4x+3x+12

= x(x+4)+3(x+4)

= (x+4)(x+3)

 

 

Factor: Non-Monic Trinomials

FORMULA

RULE

EXAMPLE

Where p and q are integers that add to b and multiply to ac

 

ax²+bx+c
= ax²+px+qx+c
= (ax+p)(a+q)

Non-monic trinomial:

     Coefficient of x² is not 1

     No common factors between the terms

 

Look for factors of ac that add to b

Split the b term

Factor in pairs

   2x2+3x+2

= 2x2+1x+2x+2

= (2x+1)(x+2)

 

 

 

Solving Quadratics

FORMULA

RULE/EXPLANATION

EXAMPLE

(x+p)(x+q)
(x+p) = 0 or
(x+q) = 0

∴ x = -p or -q

See rule for explanation

The Null Factor Law states:

 

If ab=0, then a=0 or b=0.

∴ We can solve a quadratic in binomial form in stating that:

   (x+5)(x-9)
∴ x = -5 or +9

 

  (x+4)(x-9)

∴x = -5 or +9

 

 

Quick Note: Indices

I know that this cheat sheet is Quadratics but I also forget a few indices things so I’m putting this here anyway and you can’t do anything about it.

 

RULE/EXPLANATION

EXAMPLE

Multiplying: Keep the base, add the powers
Dividing: Keep the base, subtract the powers

Power to a power: Keep the base, multiply the powers
Power of zero: x0 = 1, where x is any number

Negative indices: a-m = 1/
Make sure that for any negative indices, you move them

Fractional indices = the root

x²x x³= x5

x6 ÷ x4 = x2

(x2)3 = x6

x-9 = 1/x9

 

x1/2 = √x

x3/5 = 5√x3